Atomistry » Barium » Energy
Atomistry »
  Barium »
    Energy »

Barium Ionization Energy

The Barium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Barium.
Ba -> Ba+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Barium is:
BaN+ -> Ba(N+1)+ + e-

Ionization Energy

Ba -> Ba1+ = 502.8 kJ/mol = 120.29 Kcal/mol
Ba1+ -> Ba2+ = 965.1 kJ/mol = 230.89 Kcal/mol
Ba2+ -> Ba3+ = 3600 kJ/mol = 861.24 Kcal/mol
Ba3+ -> Ba4+ = 4700 kJ/mol = 1124.40 Kcal/mol
Ba4+ -> Ba5+ = 6000 kJ/mol = 1435.41 Kcal/mol
Ba5+ -> Ba6+ = 7700 kJ/mol = 1842.11 Kcal/mol
Ba6+ -> Ba7+ = 9000 kJ/mol = 2153.11 Kcal/mol
Ba7+ -> Ba8+ = 10200 kJ/mol = 2440.19 Kcal/mol
Ba8+ -> Ba9+ = 13500 kJ/mol = 3229.67 Kcal/mol
Ba9+ -> Ba10+ = 15100 kJ/mol = 3612.44 Kcal/mol

Last articles

Zn in 7L0B
Zn in 7KZZ
Zn in 7KZL
Zn in 7L3O
Zn in 7L52
Zn in 7L6T
Zn in 7KZ7
Zn in 7L6R
Zn in 7KKM
Zn in 7KKQ
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy