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Barium Ionization Energy

The Barium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Barium.
Ba -> Ba+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Barium is:
BaN+ -> Ba(N+1)+ + e-

Ionization Energy

Ba -> Ba1+ = 502.8 kJ/mol = 120.29 Kcal/mol
Ba1+ -> Ba2+ = 965.1 kJ/mol = 230.89 Kcal/mol
Ba2+ -> Ba3+ = 3600 kJ/mol = 861.24 Kcal/mol
Ba3+ -> Ba4+ = 4700 kJ/mol = 1124.40 Kcal/mol
Ba4+ -> Ba5+ = 6000 kJ/mol = 1435.41 Kcal/mol
Ba5+ -> Ba6+ = 7700 kJ/mol = 1842.11 Kcal/mol
Ba6+ -> Ba7+ = 9000 kJ/mol = 2153.11 Kcal/mol
Ba7+ -> Ba8+ = 10200 kJ/mol = 2440.19 Kcal/mol
Ba8+ -> Ba9+ = 13500 kJ/mol = 3229.67 Kcal/mol
Ba9+ -> Ba10+ = 15100 kJ/mol = 3612.44 Kcal/mol

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