Barium Ionization Energy

The Barium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Barium.
Ba -> Ba⁺ + e^-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Barium is:
Ba^N+ -> Ba^(N+1)+ + e^-

Ba -> Ba¹⁺ = 502.8 kJ/mol = 120.29 Kcal/mol
Ba¹⁺ -> Ba²⁺ = 965.1 kJ/mol = 230.89 Kcal/mol
Ba²⁺ -> Ba³⁺ = 3600 kJ/mol = 861.24 Kcal/mol
Ba³⁺ -> Ba⁴⁺ = 4700 kJ/mol = 1124.40 Kcal/mol
Ba⁴⁺ -> Ba⁵⁺ = 6000 kJ/mol = 1435.41 Kcal/mol
Ba⁵⁺ -> Ba⁶⁺ = 7700 kJ/mol = 1842.11 Kcal/mol
Ba⁶⁺ -> Ba⁷⁺ = 9000 kJ/mol = 2153.11 Kcal/mol
Ba⁷⁺ -> Ba⁸⁺ = 10200 kJ/mol = 2440.19 Kcal/mol
Ba⁸⁺ -> Ba⁹⁺ = 13500 kJ/mol = 3229.67 Kcal/mol
Ba⁹⁺ -> Ba¹⁰⁺ = 15100 kJ/mol = 3612.44 Kcal/mol